The equation of lines are x−3y+2=0 . . . (i) and 2x+5y−7=0 . . . (ii) On solving Eqs. (i) and (ii), we get x=1,y=1 ∴ The co-ordinates of a point of intersection of given lines are (1,1). The equation of line perpendicular to 3x+2y+5=0 is 2x−3y+λ=0. Which passes through (1,1). ∴2−3+λ=0 ⇒λ=1 ∴ Required equation of line is 2x−3y+1=0