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EAMCET Engineering 2006 Solved Paper
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© examsnet.com
Question : 5
Total: 160
A bullet of mass
10
g
is fired horizontally with a velocity
1000
ms
−
1
from a rifle situated at a height
50
m
above the ground. If the bullet reaches the ground with a velocity
500
ms
−
1
,
the work done against air resistance in the trajectory of the bullet is :
(
g
=
10
ms
−
2
)
5005
J
3755
J
3750
J
17.5
J
Validate
Solution:
From equation of motion,
v
2
=
u
2
−
2
a
s
(
500
)
2
=
(
1000
)
2
−
2
×
a
×
s
s
=
(
1000
)
2
−
(
500
)
2
2
a
=
375000
a
∴
Work done against air resistance
=
F
s
=
ma
×
s
=
10
1000
a
×
375000
a
=
3750
J
© examsnet.com
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