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EAMCET Engineering 2006 Solved Paper
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© examsnet.com
Question : 6
Total: 160
A man of
50
kg
is standing at one end on a boat of length
25
m
and mass
200
kg
. If he starts running and when he reaches the other end, he has a velocity
2
ms
−
1
with respect to the boat. The final velocity of the boat is : (in
ms
−
1
)
2
5
2
3
8
5
8
3
Validate
Solution:
Let
v
be the velocity of the boat with respect to the water, then from conservation of linear momentum.
(
200
+
50
)
v
+
50
×
2
=
50
×
0
+
200
×
0
250
v
=
−
100
v
=
−
100
250
=
−
2
5
m
∕
s
© examsnet.com
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