∵α,β,γ are the roots of the equation ‌x3−6x2+11x+6=0. ∴‌α+β+γ=6 ‌ and ‌‌αβ+βγ+γα=11 ‌ Now ‌‌Σα2β+Σαβ2‌‌αβγ=−6 ‌=α2β+β2γ+γ2α+αβ2+βγ2+γα2 ‌=αβ(α+β)+βγ(β+γ)+γα(γ+α) ‌=αβ(6−γ)+βγ(6−α)+γα(6−β) ‌=6(αβ+βγ+γα)−3αβγ ‌=6(11)+3(6) ‌=66+18=84