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EAMCET Engineering 2006 Solved Paper
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© examsnet.com
Question : 97
Total: 160
A
=
[
1
2
2
2
1
2
2
2
1
]
then
A
3
−
4
A
2
−
6
A
is equal to :
0
A
−
A
I
Validate
Solution:
∵
A
=
[
1
2
2
2
1
2
2
2
1
]
∴
A
2
=
[
1
2
2
2
1
2
2
2
1
]
[
1
2
2
2
1
2
2
2
1
]
=
[
9
8
8
8
9
8
8
8
9
]
A
3
=
A
2
⋅
A
=
[
9
8
8
8
9
8
8
8
9
]
[
1
2
2
2
1
2
2
2
1
]
=
[
41
42
42
42
41
42
42
42
41
]
∴
A
3
−
4
A
2
−
6
A
=
[
41
42
42
42
41
42
42
42
41
]
−
4
[
9
8
8
8
9
8
8
8
9
]
−
6
[
1
2
2
2
1
2
2
2
1
]
=
[
41
−
36
−
6
42
−
32
−
12
42
−
32
−
12
42
−
32
−
12
41
−
36
−
6
42
−
32
−
12
42
−
32
−
12
42
−
32
−
12
41
−
36
−
6
]
=
[
−
1
−
2
−
2
−
2
−
1
−
2
−
2
−
2
−
1
]
=
−
[
1
2
2
2
1
2
2
2
1
]
=
−
A
© examsnet.com
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