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EAMCET Engineering 2007 Solved Paper
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© examsnet.com
Question : 6
Total: 160
Two bodies of
6
kg
and
4
kg
masses have their velocity
5
^
i
−
2
^
j
+
10
^
k
and
10
^
i
−
2
^
j
+
5
^
k
respectively. Then the velocity of their centre of mass is
5
^
i
+
2
^
j
−
8
^
k
7
^
i
+
2
^
j
−
8
^
k
7
^
i
−
2
^
j
+
8
^
k
5
^
i
−
2
^
j
+
8
^
k
Validate
Solution:
Given,
m
1
=
6
kg
,
m
2
=
4
kg
→
v
1
=
5
^
i
−
2
^
j
+
10
^
k
,
→
v
2
=
10
^
i
−
2
^
j
+
5
^
k
The velocity of centre of mass is
→
v
=
m
1
→
v
1
+
m
2
→
v
2
m
1
+
m
2
=
6
(
5
^
i
−
2
^
j
+
10
^
k
)
+
4
(
10
^
i
−
2
^
i
+
5
^
k
)
6
+
4
=
70
^
i
−
20
^
j
+
80
^
k
10
=
7
^
i
−
2
^
j
+
8
^
k
© examsnet.com
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