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EAMCET Engineering 2007 Solved Paper
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© examsnet.com
Question : 7
Total: 160
In two separate collisions, the coefficient of restitutions
e
1
and
e
2
are in the ratio
3
:
1
. In the first collision the relative velocity of approach is twice the relative velocity of separation, then the ratio between relative velocity of approach and the relative velocity of separation in the second collision is
1
:
6
2
:
3
3
:
2
6
:
1
Validate
Solution:
Coefficient of restitution is given by
e
=
relative velocity of separation
relative velocity of approach
we have
e
1
=
1
2
and
e
2
=
(
relative velocity of separation
relative velocity of approach
)
2
Given,
e
1
e
2
=
3
1
⇒
e
2
e
1
=
1
3
⇒
(
relative velocity of separation
relative velocity of approach
)
2
=
1
3
×
1
2
=
1
6
⇒
(
relative velocity of approach
relative velocity of separation
)
2
=
6
1
© examsnet.com
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