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EAMCET Engineering 2008 Solved Paper
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© examsnet.com
Question : 137
Total: 160
For an ellipse with eccentricity
1
2
the centre is at the origin. If one directrix is
x
=
4
, then the equation of the ellipse is
3
x
2
+
4
y
2
=
1
3
x
2
+
4
y
2
=
12
4
x
2
+
3
y
2
=
1
4
x
2
+
3
y
2
=
12
Validate
Solution:
Given that,
e
=
1
2
and
a
e
=
4
⇒
a
1
∕
2
=
4
⇒
a
=
2
Using
b
2
=
a
2
(
1
−
e
2
)
⇒
b
2
=
4
(
1
−
1
4
)
=
3
∴
Equation of ellipse is
x
2
4
+
y
2
3
=
1
⇒
3
x
2
+
4
y
2
=
12
© examsnet.com
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