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EAMCET Engineering 2008 Solved Paper
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© examsnet.com
Question : 138
Total: 160
The distance between the foci of the hyperbola
x
2
−
3
y
2
−
4
x
−
6
y
−
11
=
0
is
4
6
8
10
Validate
Solution:
Given, equation of hyperbola is
x
2
−
3
y
2
−
4
x
−
6
y
−
11
=
0
⇒
(
x
2
−
4
x
+
4
)
−
3
(
y
2
+
2
y
+
1
)
−
11
=
4
−
3
⇒
(
x
−
2
)
2
−
3
(
y
+
1
)
2
=
12
⇒
(
x
−
2
)
2
12
−
(
y
+
1
)
2
4
=
1
∴
Distance between foci
=
2
a
e
=
2
×
√
12
×
2
√
3
=
8
© examsnet.com
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