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EAMCET Engineering 2008 Solved Paper
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Section:
Mathematics
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© examsnet.com
Question : 88
Total: 160
If
n
P
r
=
30240
and
n
C
r
=
252
, then the ordered pair
(
n
,
r
)
is equal to
(
12
,
6
)
(
10
,
5
)
(
9
,
4
)
(
16
,
7
)
Validate
Solution:
Given that,
n
P
r
=
30240
and
n
C
r
=
252
⇒
n
!
(
n
−
r
)
!
=
30240
and
n
!
(
n
−
r
)
!
r
!
=
252
⇒
r
!
=
30240
252
=
120
⇒
r
=
5
∴
n
!
(
n
−
5
)
!
=
30240
⇒
n
(
n
−
1
)
(
n
−
2
)
(
n
−
3
)
(
n
−
4
)
=
30240
⇒
n
(
n
−
1
)
(
n
−
2
)
(
n
−
3
)
(
n
−
4
)
=
10
(
10
−
1
)
(
10
−
2
)
(
10
−
3
)
(
10
−
4
)
⇒
n
=
10
Hence, required ordered pair is
(
10
,
5
)
.
© examsnet.com
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