akxk ⇒(1+x)10=a0x0+a1x+a2x2+...+a15x15 ⇒‌‌‌10C0+‌10C1x+‌10C2x2+...+‌10C10x10 =a0+a1x+a2x2+a3x3+...+a15x15 On equating the coefficient of constant and even powers of x, we get a0‌=‌10C0,a2=‌10C2 a4‌=‌10C4,...,a10=‌10C10 a12‌=a14=0 ∴