p(x)=x4−4x3+2⇒P(−x)=x4+4x3+2
Number of real
(+ve) roots
≤ Number of sign changes in
p(x)=2 Number of real
(−ve) rots
≤ Number of sign changes in
p(−x)=0 So,
p(x)=0 has no
(−ve) real roots and a maximum of
2(+ve) real roots
∴ Number of real roots of '
P(x)=0′≤2 }One real root lies between 0 & 1
P(3)=81−108+2<0 |
P(4)=256−256+2>0 |
}One real root lies between 3 & 4
P(x) has only two real roots.
One real root lies in (0, 1) and One real root lies is (3, 4)