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GATE Mathematics 2014 Paper

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Question : 32

Total: 55

The integral surface of the first order partial differential equation 2y(z−3)

=y(2x−3) passing through the curve x2+y2=2x,z=0 is

x2+y2−z2−2x+4z=0
x2+y2−z2−2x+8z=0
x2+y2+z2−2x+16z=0
x2+y2+z2−2x+8z=0

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