Given: 3 married couples have bought 6 seats in the same row for a talent show. Formula used: n! = n × (n – 1) × (n – 2) ……………………….3 × 2 × 1 Calculation: Each couple sits in pairs- same as the above, but there are 3 couples so 3! Each couple also has two ways of sitting So we need to multiply this by 2 for each so 3 time’s total.⇒3!×(2)3 ⇒ 3 × 2 × 1 × 8 =48 ∴ Different ways can they be seated if each couple is to sit together 48