According to questions. AB = 2 km BC = 5 km, CD = 8 km, DE = 5 km EF = 1 km, BC = DE = 5 km, CD = BE = 8 km BE = EF + AF + AB ∴ AF = BE – (EF + AB) = 8 – (1 + 2) = 8 – 3 = 5 km ∴ Required distance = AF = 5 km and required direction is North