IBPS RRB Officer Prelims 14 Nov 2016 Shift 2 Paper

(4) Number of assistant professors in university J
=

300×72

100

=216
Number of professors
= (300 – 216) – 52
= 84 – 52 = 32
Number of assistant professors in university K
=

250×40

100

=100
Number of professors
= (250 –100) – 72
= 150 – 72 = 78
∴ Total number of professors = 32 + 78 = 110
Number of assistant professors in university L = 96
∴ Required per cent
=

110−96

96

×100
= 1400/ 96 ≈ 15