Statement II: When (N3 – N) is divided by 6, remainder is 0. (N3–N) = N(N2–1) = N(N – 1)(N + 1) It is the product of 3 consecutive numbers. We already know that the product of 3 consecutive numbers is always completely divisible by 6. Hence, nothing can be concluded from statement II alone. Statement I: When the number N is divided by 18, reminder is 8. So, we can write: N = 18a + 8 ⇒ N = 6 × (3a + 1) + 2 When the number is divided by 6, the remainder will be 2 only. ∴ Statement I alone is sufficient to answer the question.