IBPS SO Prelims Exam Model Paper 8

Calculation:
Total student of mechanical branch = (

21

100

) × 800 = 168
⇒ Boys in mechanical branch = (

4

7

) × 168 = 96
⇒ Girls in mechanical branch = (

3

7

) × 168 = 72
According to the question:
Boys in computer science branch = 3 × Girls in mechanical branch
⇒ Boys in computer science = 3 × 72 = 216
⇒ Girls in computer science = (

5

6

) × 216 = 180
Student in civil branch = 800 – (96 + 72 + 216 + 180) = 236
⇒ Boys in civil = (

3

4

) × 236 = 177
⇒ Girls in civil = (

1

4

) × 236 = 59
So by these details, the below is formedTotal boys of mechanical and civil = 96 + 177 = 273
Total girls of mechanical and civil = 72 + 59 = 131
∴ Required ratio = 273 : 131