Given: Pure alcohol in container A = 25 litres
Pure water in container B = 25 litres
Concept: When the mixture is taken out, components are taken out in the respective ratio.
Calculation: Container-A Container-B
Alcohol Water Alcohol Water
Initially→ 25 0 0 25
After 1st process→ 20 0 5 25
Now, ratio of alcohol to water in container B = 5 : 25 = 1 : 5
After 2nd process,
Water in container A = 6 ×
= 5 litres
Water in container B = 25 –
× 6 = 20 litres
∴ Ratio of water in A & B = 5 ∶ 20 = 1 ∶ 4