Let the amount invested in X = x Thus, the amount invested in Y=25000−x The interest incurred = 3518 Rs, thus the total amount at the end of the 2nd year = 28518 Rs Thus x×(1.06)2+(25000−x)×(1.08)2=28518
⇒x×1.1236+25000×1.11664−x×1.11664=28518
⇒−0.0428x+29160=28518 ⇒642=0.0428x Hence,x=15000‌Rs Hence, option C is the correct answer.