Indian Institute of Foreign Trade 2012 Solved Paper

Each of the 5 papers can be checked by any of the 9 professors and thus the total number of way =95
Selecting exactly 2 of the 9 professors can be done in 9C2 way = 36
They can correct the 5 papers in 25−2(all the 5 papers checked by the same professor) = 30 ways.
Thus, the total number of ways 36×30
Hence, the required probability =

36×30

95

=

40

2187

Hence, option B is the correct answer.