Assuming that the TestResult.txt file exists and given the code fragment: public class TestReadFile { public void readFile(String fName) throws IOException { /* Line n1*/ Stream content = Files.lines(p); content.forEach(s1 -> System.out.println(s1)); } public static void main(String[] args) throws IOException { TestReadFile trf = new TestReadFile(); trf.readFile("TestResult.txt "); } }
Which code fragment at Line n1 compiles?

Question

Assuming that the TestResult.txt file exists and given the code fragment:

public class TestReadFile {  
    public void readFile(String fName) throws IOException {  
        /* Line n1*/  
        Stream content = Files.lines(p);  
        content.forEach(s1 -> System.out.println(s1));  
    }  
    public static void main(String[] args) throws IOException { 
        TestReadFile trf = new TestReadFile(); 
        trf.readFile("TestResult.txt ");  
    } }

Which code fragment at Line n1 compiles?

Examsnet · Accepted Answer

Correct Answer is : Path p = Paths.get(fName);

Java SE 8 Programmer II (1Z0-809)