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JEE Advanced 2015 Paper 1
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© examsnet.com
Question : 3
Total: 60
Consider a hydrogen atom with its electron
n
t
h
orbital.An electromagnetic radiation of wavelength 90 nm is used to ionize the atom.If the kinectic energy of the ejected electron is 10.4 eV,then the value of n is (hc=1242 eV nm)
Your Answer:
Validate
Solution:
E
p
h
o
t
o
n
=
E
i
o
n
i
z
e
a
t
o
m
+
E
k
i
n
e
t
i
c
e
n
e
r
g
y
1242
90
=
13.6
n
2
+
10.4
from this n=2
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