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JEE Advanced 2015 Paper 1
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© examsnet.com
Question : 4
Total: 60
A bullet is fired vertically upwards with velocity v from the surface of a spherical planet.When it reaches its maximum height,its acceleration due to planet's gravity is
1
4
t
h
of its value at the surface of the planet.I the escape velocity from the planet is
v
e
s
c
=
v
√
n
.then the value of N is(ignore energy loss due to atmosphere)
v
√
2
v
√
8
v
√
4
v
√
7
Validate
Solution:
At height R fro the surface of planet acceleration due to planet's gravity is
1
4
t
h
in comparison to the value at the surface
So.
−
GMm
/
R
+
1
2
m
v
2
=
−
G
M
m
R
+
R
+
1
2
m
v
e
s
c
2
=
0
∴
V
e
s
c
=
v
√
2
© examsnet.com
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