Let the currents through inductors be i2 and i2. Then VL=
L1di1
dt
=L2
di2
dt
i.e.,
t
∫
0
d(Lii1)=
t
∫
0
d(L2i2)⇒L1i1=L2i2 i.e.,
i1
i2
=
L2
L1
is fixed at all times Hence (D) is correct Also, since inductor acts as an open circuit at t = 0, current through all branches is zero at t = 0. After a long time current through battery i0=