Examsnet
Unconfined exams practice
Home
Exams
Banking Entrance Exams
CUET Exam Papers
Defence Exams
Engineering Exams
Finance Entrance Exams
GATE Exam Practice
Insurance Exams
International Exams
JEE Exams
LAW Entrance Exams
MBA Entrance Exams
MCA Entrance Exams
Medical Entrance Exams
Other Entrance Exams
Police Exams
Public Service Commission (PSC)
RRB Entrance Exams
SSC Exams
State Govt Exams
Subjectwise Practice
Teacher Exams
SET Exams(State Eligibility Test)
UPSC Entrance Exams
Aptitude
Algebra and Higher Mathematics
Arithmetic
Commercial Mathematics
Data Based Mathematics
Geometry and Mensuration
Number System and Numeracy
Problem Solving
Board Exams
Andhra
Bihar
CBSE
Gujarat
Haryana
ICSE
Jammu and Kashmir
Karnataka
Kerala
Madhya Pradesh
Maharashtra
Odisha
Tamil Nadu
Telangana
Uttar Pradesh
English
Competitive English
Certifications
Technical
Cloud Tech Certifications
Security Tech Certifications
Management
IT Infrastructure
More
About
Careers
Contact Us
Our Apps
Privacy
Test Index
JEE Advanced 2018 Paper 1
Show Para
Hide Para
Share question:
© examsnet.com
Question : 5
Total: 54
Two infinitely long straight wires lie in the xy-plane along the lines
x
=
±
R
The wire located at
x
=
+
R
carries a constant current
I
1
and the wire located at
x
=
−
R
carries a constant current
I
2
.A circular loop of radius R is suspended with its centre at
(
0
,
0
,
√
3
R
)
and in a plane parallel to the xy-plane. This loop carries a constant current I in the clockwise direction as seen from above the loop. The current in the wire is taken to be positive if it is in the
+
−
j
direction. Which of the following statements regarding the magnetic field
−
B
is (are) true ?
If
I
1
=
I
2
then
−
B
cannot be equal to zero at the origin
(
0
,
0
,
0
)
If
I
1
>
0
and
I
2
<
0
then
−
B
can be equal to zero at the origin
(
0
,
0
,
0
)
If
I
1
<
0
and
I
2
>
0
then
−
B
can be equal to zero at the origin
(
0
,
0
,
0
)
If
I
1
=
I
2
,then the z-component of the magnetic field at the centre of the loop is
(
−
µ
0
I
2
R
)
Validate
Solution:
A) At origin,
−
B
=
0
due to two wries if
I
1
=
I
2
,hence
−
B
net
at origin is equal to
−
B
due to ring, which is non-zero
B) If
I
1
>
0
and
I
2
<
0
,
−
B
at origin due to wires will be along
+
−
k
direction and
−
B
due to ring is along
−
−
k
direction and hence
−
B
can be zero at origin.
C) If
I
1
<
0
and
I
2
>
0
,at origin due to wires along
−
−
k
and also along
−
−
k
due to ring , hence
−
B
cannot be zero
D) At centre of ring,
−
B
due to wires is along x-axis.
© examsnet.com
Go to Question:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
Prev Question
Next Question