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JEE Advanced 2020 Full Test 1 Paper 1
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© examsnet.com
Question : 14
Total: 54
The surface mass density (mass per unit area) of a semi circular disc of radius
R
varies as
σ
=
|
→
a
×
→
r
|
,
where
→
a
is a constant velocity along positive
x
axis and
→
r
is positive vector with respect to origin. It is kept on smooth horizontal surface with flat surface in contact with surface. Now, force
F
' is applied in such a way that it moves translationally without any rotation. The value of
h
is
k
π
R
16
then find value of
k
.
Your Answer:
Validate
Solution:
Disc will move translationally if line of action of force passes through
c
.
m
of semi circular disc.
y
c
m
=
∫
y
d
m
∫
d
m
=
3
π
R
16
So value of
K
=
3
© examsnet.com
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