JEE Advanced 2021 Paper 1

Paragraph for next 2 questions The boiling point of water in a $0.1$ molal silver nitrate solution (solution $A$ ) is $x^{\circ}\,\mathrm{C}$. To this solution $A$, an equal volume of $0.1$ molal aqueous barium chloride solution is added to make a new solution B. The difference in the boiling points of water in the two solutions A and B is y $\times 10^{-2}\,{}^\circ\mathrm{C}$. (Assume : Densities of the solutions A and B are the same as that of water and the soluble salts dissociate completely.) Use: Molal elevation constant (Ebullioscopic Constant), $K_{b}=0.5\,\mathrm{K}\,\mathrm{kg}\,\mathrm{mol}^{-1}$; Boiling point of pure water as $100^{\circ}\,\mathrm{C}$.)