JEE Advanced 2021 Paper 2

Paragraph for next 2 questions A sample $(5.6\,\mathrm{g})$ containing iron is completely dissolved in cold dilute $\mathrm{HCl}$ to prepare a $250\,\mathrm{mL}$ of solution. Titration of $25.0\,\mathrm{mL}$ of this solution requires $12.5\,\mathrm{mL}$ of $0.03\,\mathrm{M}\,\mathrm{KMnO}_4$ solution to reach the end point. Number of moles of $\mathrm{Fe}^{2+}$ present in $250\,\mathrm{mL}$ solution is $x \times 10^{-2}$ (consider complete dissolution of $\mathrm{FeCl}_2$ ). The amount of iron present in the sample of $y \%$ by weight. (Assume: $\mathrm{KMnO}_4$ reacts only with $\mathrm{Fe}^{2+}$ in the solution Use : Molar mass of iron as $56\,\mathrm{g}\,\mathrm{mol}^{-1}$ )