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JEE Advanced Model Paper 15 with solutions for online practice
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© examsnet.com
Question : 16
Total: 60
A diathemic piston of mass M, cross section area A separate the volume inside a horizontal adiabatic cylinder of length 2
I
0
in two equal parts. Each chamber contains an ideal gas and pressure on each side is P. The piston can move without friction and is attached with a spring of spring constant K as shown. Initially the spring is non-deformed. The piston is given a small displacement x towards left. Then
The pressure in left chamber increases
The pressure in right chamber decreases
The piston oscillates with time period 2π
√
M
I
0
2
P
A
+
I
0
K
The piston oscillates with time period 2π
√
M
I
0
P
A
+
I
0
K
Validate
Solution:
The FBD of the piston is
Restoring force =
(
P
2
−
P
1
)
A + Kx
- Ma =
(
P
2
−
P
1
)
A + Kx
Also
P
1
A
(
l
0
) - x = PA
l
0
P
1
=
P
l
0
l
0
−
x
.... (i)
P
2
A
(
l
0
+
x
)
=
P
A
l
0
P
2
=
P
l
0
l
0
+
x
..... (ii)
From (i) and (ii) a =
[
2
P
l
0
A
l
0
2
−
x
2
+
K
]
x
M
Since x ≪
l
0
a =
[
2
P
l
0
A
l
0
2
−
x
2
+
K
]
x
M
∴ T = 2π
√
M
I
0
2
P
A
+
K
I
0
© examsnet.com
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