If Li+ ions fit exactly into octahedral void of LiCl , 2rLi+ + 2Cl− = 5.14 ⇒ 2=rLi+ + rCl− = 2.57 Cl− ions occupies comers of the face as well as center of face Let distance between the centers of two chlorides ions be “a” and distance between Li+ and Cl" be “b” ⇒ b = 2.57 Radius of Cl− =