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JEE Advanced Model Paper 5 with solutions for online practice
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© examsnet.com
Question : 40
Total: 54
The sixth term in the expansion of
[
2
l
o
g
2
√
9
x
−
1
+
7
+
1
2
1
5
l
o
g
2
(
3
x
−
1
+
1
)
]
7
is equal to 84. Then the number of values of xis equal to
The remainder when (
2
100
+ 1) is divided by 3
The remainder when
2
100
is divided by 3
The number of rational terms in expansion of
(
2
3
∕
7
+
3
2
∕
7
)
7
The number of rational terms in expansion of
(
2
3
7
+
3
2
7
)
25
Validate
Solution:
Answer (A, C)
2
l
o
g
2
√
9
x
−
1
+
7
=
√
9
x
−
1
+
7
2
1
5
l
o
g
2
(
3
x
−
1
+
1
)
=
(
3
x
−
1
+
1
)
1
5
∴ Sixth term =
7
C
5
(
√
9
x
−
1
+
7
)
2
.
1
3
x
−
1
+
1
= 84
∴
3
x
−
1
= 1 , 3 ⇒ x = 1 , 2
2
100
+ 1 = 1 +
4
50
= 1 +
(
3
+
1
)
50
= 2 +
50
C
1
. 3 +
50
C
2
.
3
2
+ ...
Remainder = 2
© examsnet.com
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