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JEE Advanced Paper 1 2024 Paper

PART-II : PHYSICS

SECTION 1

• This section contains FOUR (04) questions.
• Each question has FOUR options (A), (B), (C) and (D). ONLY ONE of these four options is the correct answer.

Question : 21

Total: 51

A block of mass 5 kg moves along the x-direction subject to the force F=(−20x+10)N, with the value of x in metre. At time t=0 s, it is at rest at position x=1m. The position and momentum of the block at t=(π∕4) s are

−0.5m,5‌kg‌m∕ s
0.5m,0‌kg‌m∕ s
0.5m,−5‌kg‌m∕ s
−1m,5‌kg‌m∕ s

Validate

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