The circuit shown in the figure contains an inductor L, a capacitor C₀, a resistor R₀ and an ideal battery. The circuit also contains two keys K₁ and K₂. Initially, both the keys are open and there is no charge on the capacitor. At an instant, key K₁ is closed and immediately after this the current in R₀ is found to be I₁. After a long time, the current attains a steady state value I₂. Thereafter, K₂ is closed and simultaneously K₁ is opened and the voltage across C₀ oscillates with amplitude V₀ and angular frequency ω₀. Match the quantities mentioned in List-I with their values in List-II and choose the correct option. List-I List-II (P) The value of l₁ in Ampere is (1) 0 (Q) The value of l₂ in Ampere is (2) 2 (R) The value of ω₀ in kilo-radians/s is (3) 4 (S) The value of V₀ in Volt is (4) 20 (5) 200 [JEE Adv 2024 P1]

Question

Examsnet · Accepted Answer

Correct Answer is : P → 1; Q → 3; R → 2; S → 5

	List-I		List-II
(P)	The value of $l_{1}$ in Ampere is	(1)	0
(Q)	The value of $l_{2}$ in Ampere is	(2)	2
(R)	The value of $\omega_{0}$ in kilo-radians/s is	(3)	4
(S)	The value of $V_{0}$ in Volt is	(4)	20
		(5)	200

Alternating Current