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Alternating Current

Section: Physics

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Question : 3

Total: 13

A series LCR circuit is connected to a 45sin‌(ωt) Volt source. The resonant angular frequency of the circuit is 105‌rad‌ s−1 and current amplitude at resonance is I0. When the angular frequency of the source is ω=8×104 rad s‌−1, the current amplitude in the circuit is 0.05I0. If L=50‌mH, match each entry in List-I with an appropriate value from List-II and choose the correct option.

List-I	List-II
(P) I0 in mA	(1) 44.4
(Q) The quality factor of the circuit	(2) 18
(R) The bandwidth of the circuit in rad s	(3) 400
(S) The peak power dissipated at resonance in Watt	(4) 2250
	(5) 500

[JEE Adv 2023 P1]

P→2,Q→3,R→5,S→1
P→3,Q→1,R→4,S→2
P→4,Q→5,R→3,S→1
P→4,Q→2,R→1,S→5

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