Number of turns in the primary side
Np=300 Number of turns in the secondary side
Ns=150 The output power or the secondary side power is
Po=2.2kW=2200W The current in the secondary coil is
Is=10A We know that Ohm's law is given by the formula
PO=VOIO−−(i) Hence by using Ohm's law, we can calculate the output voltage of the transformer
VO= ⟹VO= ∴VO=220V Hence the secondary voltage or the output voltage of the transformer is
=220V Now we know that the ratio of the number of turns in the secondary coil to the number of turns in the primary coil is equal to the ratio of the output voltage to the input voltage, hence we can write
n== Now we substitute the values
= = Vi=×220 =220×2 =440V Hence the input voltage or the primary voltage of the transformer is
=440V We also know that the ratio
n is equal to the ratio of current in the secondary side to the current on the primary side, so we can write
n== Hence by substituting the values
= = ⟹Ii=×10 =20A So, the current in the primary coil
=20A