At neutral point g = 0 so graph (C) is correct
Given,
Acceleration due to gravity on Earth,
gE=10m∕s2and acceleration due to gravity on Mars,
gM=4m∕s2We know that,
gE (at height
h)=gEarth (1−)∴ Weight at Earth,
mgE=100×10=1000NAs the spaceship moves far away from Earth, the value of
gE decreases to zero at a point where
gE+gM=0 and hence weight will also be zero.
This point is called neutral point and is shown by graph (c) in the given figure.
Then,
gE increases
4ms−2 at Mars surface and weight becomes
400N which is also exhibited by graph (c).