Which is not in options therefore it must be bonus. But according to history of JEE-Mains it seems they had following line of thinking Given curves are y=4−x2 and y=|x|
There are two circles satisfying the given conditions. The circle shown is of least area. Let radius of circle is 'r ∴ co-ordinates of centre =(0,4–r) ∵circle touches the line y = x in first quadrant ∴|
0−(4−r)
√2
|=r⇒r−4=±r√2 ∴r=4(√2−1)which is given in option 4.