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JEE Main 26-Aug-2021 Shift 1 Solved Paper
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© examsnet.com
Question : 29
Total: 90
White light is passed through a double slit and interference is observed on a screen
1.5
m
away. The separation between the slits is
0.3
mm
. The first violet and red fringes are formed
2.0
mm
and
3.5
mm
away from the central whitefringes. The difference in wavelengths of red and violet light is ......
nm
.
[26 Aug 2021 Shift 1]
Your Answer:
Validate
Solution:
In a Young’s double slit experiment for interference pattern, the position of bright fringe is given by
y
n
=
n
λ
D
d
Here, D = 1.5 m,
d
=
0.3
×
10
−
3
×
m
and n = 1
λ
=
y
n
d
D
For first violet,
y
n
=
2
mm
=
2
×
10
−
3
m
∴
λ
violet
=
2
×
10
−
3
d
D
For first red
y
n
=
3.5
mm
=
3.5
×
10
−
3
m
λ
red
=
3.5
×
10
−
3
d
D
The difference in wavelengths of red and violet light is
Δ
λ
=
λ
red
−
λ
violet
=
3.5
×
10
−
3
d
D
−
2
×
10
−
3
d
D
=
d
D
(
1.5
)
×
10
−
3
=
0.3
×
10
−
3
1.5
×
1.5
×
10
−
3
=
0.3
×
10
−
6
=
0.3
×
10
−
6
×
10
3
×
10
−
3
=
300
×
10
−
9
=
300
nm
© examsnet.com
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