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JEE Main 26-Aug-2021 Shift 1 Solved Paper
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© examsnet.com
Question : 30
Total: 90
Consider a badminton racket with length scales as shown in the figure.
If the mass of the linear and circular portions of the badminton racket are same (M) and the mass of the threads are negligible, the moment of inertia of the racket about an axis perpendicular to the handle and in the plane of the ring at,
r
2
distance from the end A of the
handle will be ........
M
r
2
.
[26 Aug 2021 Shift 1]
Your Answer:
Validate
Solution:
The given situation is shown in the following figure
The moment of inertia of the racket about an axis perpendicular to the handle and in the plane of ring at,
r
2
distance from end A of the handle is given by
I
=
I
due
to
handle
+
I
due
to
disc
...(i)
I
due
to
handle
=
1
12
M
(
6
r
)
2
+
M
(
5
r
2
)
2
=
1
12
M
36
r
2
+
25
M
r
2
4
=
3
M
r
2
+
25
4
M
r
2
=
M
r
2
(
37
4
)
=
37
4
M
r
2
I
due
to
disc
=
M
r
2
2
+
M
(
13
r
2
)
2
=
M
r
2
2
+
169
M
r
2
4
=
171
Mr
2
4
∴ From Eq. (i), we get
I
=
I
dueto
handle
+
I
due
to
disc
=
37
4
M
r
2
+
171
M
r
2
4
=
208
4
M
r
2
=
52
Mr
2
© examsnet.com
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