Solution:
∵ Sum of all entries of matrix A must be prime p such that 2<p<8 then sum of entries may be 3,5 or 7 .
If sum is 3 then possible entries are (0,0,0,3),(0,0,1,2) or (0,1,1,1).
∴ Total number of matrices =4+4+12=20
If sum of 5 then possible entries are
(0,0,0,5),(0,0,1,4),(0,0,2,3),(0,1,1,3),(0,1,2,2) and (1,1,1,2).
∴ Total number of matrices =4+12+12+12+12+4=56
If sum is 7 then possible entries are
(0,0,2,5),(0,0,3,4),(0,1,1,5),(0,3,3,1),(0,2,2,3),(1,1,1,4),(1,2,2,2),(1,1,2,3) and (0,1,2,4).
Total number of matrices with sum 7=104
∴ Total number of required matrices
=20+56+104= 180
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