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Test Index
JEE Main 29-Jan-2024 Shift 1 Solved Paper
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Section:
Physics
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© examsnet.com
Question : 31
Total: 90
In the given circuit, the breakdown voltage of the Zener diode is
3.0
V
. What is the value of
I
z
?
[29-Jan-2024 Shift 1]
3.3
mA
5.5
mA
10
mA
7
mA
Validate
Solution:
👈: Video Solution
V
z
=
3
V
Let potential at
B
=
0
V
Potential at
E
(
V
E
)
=
10
V
V
C
=
V
A
=
3
V
I
z
+
I
1
=
I
I
=
10
−
3
1000
=
7
1000
A
I
1
=
3
2000
A
Therefore
I
z
=
7
−
1.5
1000
=
5.5
mA
© examsnet.com
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