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Test Index
JEE Main 29-Jan-2024 Shift 2 Solved Paper
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Section:
Mathematics
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© examsnet.com
Question : 17
Total: 90
Let
y
=
log
e
(
1
−
x
2
1
+
x
2
)
,
−
1
<
x
<
1
. Then at
x
=
1
2
, the value of
225
(
y
′
−
y
′
′
)
is equal to
[29-Jan-2024 Shift 2]
732
746
742
736
Validate
Solution:
👈: Video Solution
y
=
log
e
(
1
−
x
2
1
+
x
2
)
d
y
d
x
=
y
′
=
−
4
x
1
−
x
4
Again,
d
2
y
d
x
2
=
y
′
′
=
−
4
(
1
+
3
x
4
)
(
1
−
x
4
)
2
Again
y
′
−
y
′
′
=
−
4
x
1
−
x
4
+
4
(
1
+
3
x
4
)
(
1
−
x
4
)
2
at
x
=
1
2
,
y
′
−
y
′
′
=
736
225
Thus
225
(
y
′
−
y
′
′
)
=
225
×
736
225
=
736
© examsnet.com
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