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JEE Main 31-Jan-2024 Shift 2 Solved Paper
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Section:
Mathematics
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© examsnet.com
Question : 4
Total: 90
Let a variable line passing through the centre of the circle
x
2
+
y
2
−
16
x
−
4
y
=
0
, meet the positive co-ordinate axes at the point
A
and
B
. Then the minimum value of
OA
+
OB
, where
O
is the origin, is equal to
[31-Jan-2024 Shift 2]
12
18
20
24
Validate
Solution:
👈: Video Solution
(
y
−
2
)
=
m
(
x
−
8
)
⇒
x
-intercept
⇒
(
−
2
m
+
8
)
⇒
y
-intercept
⇒
(
−
8
m
+
2
)
⇒
OA
+
OB
=
−
2
m
+
8
−
8
m
+
2
f
′
(
m
)
=
2
m
2
−
8
=
0
⇒
m
2
=
1
4
⇒
m
=
−
1
2
⇒
f
(
−
1
2
)
=
18
⇒
Minimum
=
18
© examsnet.com
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