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JEE Main 8 April 2017 Solved Paper Solved Paper
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© examsnet.com
Question : 2
Total: 90
A car is standing 200 m behind a bus,which is also at rest.The two start moving at the same instant but with different forward accelerations.The bus has acceleration
2
m
/
s
2
and the car has acceleration
4
m
/
s
2
.The car will catch up with the bus after a time of :
√
110
s
√
120
s
10
√
2
s
15 s
Validate
Solution:
Acceleration of Car,
a
C
=
4
m
∕
s
2
Acceleration of bus,
a
B
=
2
m
∕
s
2
Initial distance between them,
S
=
200
m
Acceleration of Car with respect to bus,
a
C
B
=
a
C
−
a
B
=
4
−
2
=
2
m
∕
s
2
As initially both are at rest
s
o
0
,
u
C
B
=
0
∴
S
=
U
C
B
×
t
+
1
2
a
C
B
×
t
2
⇒
200
=
0
+
1
2
×
2
×
t
2
⇒
t
2
=
200
⇒
t
=
10
√
2
s
e
c
.
© examsnet.com
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