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JEE Main 9 Jan 2019 Shift 2 Solved Paper

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Question : 7

Total: 90

A particle is executing simple harmonic motion(SHM) of amplitude A, along the x-axis, aboutx = 0. When its potential Energy (PE) equalskinetic energy (KE), the position of the particlewill be :

A
2
A
2√2
A
√2
A

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