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JEE Main 9 Jan 2019 Shift 2 Solved Paper
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© examsnet.com
Question : 8
Total: 90
A musician using an open flute of length 50 cm produces second harmonic sound waves. A person runs towards the musician from another end of a hall at a speed of 10 km/h. If the wave speed is 330 m/s, the frequency heard by the running person shall be close to :
753 Hz
500 Hz
333 Hz
666 Hz
Validate
Solution:
Frequency of the sound produced by flute,
f =
2
(
v
2
l
)
=
2
×
330
2
×
0.5
= 660 Hz
Velocity of observer ,
v
0
= 10 ×
5
18
=
24
9
m/s
∴ frequency detected by observer , f' =
[
v
+
v
0
v
]
f
∴ f' =
[
25
9
+
330
330
]
660
= 335.56 × 2 = 671.12
∴ closest answer is (4)
© examsnet.com
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