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JEE Main 9 Jan 2019 Shift 2 Solved Paper
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© examsnet.com
Question : 9
Total: 90
In a communication system operating at wavelength 800 nm, only one percent of source frequency is available as signal bandwidth. The number of channels accomodated for transmitting TV signals of band width 6 MHz are (Take velocity of light c = 3 ×
10
8
m/s,h= 6.6 ×
10
–
34
J-s)
3.75 ×
10
6
4.87 ×
10
5
3.86 ×
10
6
6.25 × 5
Validate
Solution:
f =
3
×
10
8
8
×
10
−
7
=
30
8
×
10
14
Hz
= 3.75 ×
10
14
Hz
1% of f = 0.0375 ×
10
14
Hz
= 3.75 ×
10
12
Hz = 3.75 ×
10
6
MHz
number of channels =
3.75
×
10
6
6
= 6.25 ×
10
5
∴ correct answer is (4)
© examsnet.com
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