Given, mass of organic compound 0.1840g Total pressure =758mm of Hg Aqueous tension =14mm of Hg Partial pressure of dry N2=758−14 =744mm of Hg For N2 V=30mL=0.03L T=287K p=744mm of Hg=
744
760
atm So, moles of N2(n)=
pV
RT
=
744
760
×
0.03
0.0821×287
n=1.25×10−3 moles of N2 Weight of N2= Moles × Molar mass =1.25×10−3×28 =35×10−3g % composition of N2 =