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JEE Main Chemistry Class 11 The P-Block Elements (Group 13-14) Questions
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© examsnet.com
Question : 1
Total: 91
The number of neutrons present in the more abundant isotope of boron is '
x
'. Amorphous boron upon heating with air forms a product, in which the oxidation state of boron is '
y
'. The value of
x
+
y
is ...
[5 Apr 2024 Shift 1]
4
6
3
9
Validate
Solution:
More abundant isotope
=
B
11
[Number of neutrons
=
6
]
x
=
6
B
+
O
2
⟶
B
2
O
3
Oxidation state of
B
in
B
2
O
3
=
+
3
So,
y
=
3
Hence
x
+
y
=
9
© examsnet.com
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